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IBM 000-735 Exam publish by Pass4side
VUE/Prometric Code:000-735
Exam Name:DB2 9.5 SQL Procedure Developer
Questions and Answers:99 Q&As
Updated:2008-12-29

1. Given the statement shown below:
SELECT ROW CHANGE TOKEN FOR dept, RID_BIT (dept)
FROM dept WHERE deptno = ‘A00′ WITH UR
Which two statements are true? (Choose two.)
A. The statement is selecting two columns from DEPT table.
B. The statement will allow the latest ROW CHANGE TOKEN value to be returned.
C. The statement will allow the earliest ROW CHANGE TOKEN value to be returned.
D. The statement will return a TIMESTAMP value.
E. The statement uses optimistic locking.
Answer: BE

2. Which CREATE PROCEDURE statement option should be used if you plan on issuing a DECLARE GLOBAL
TEMPORARY TABLE statement from within the SQL procedure body?
A. CONTAINS SQL
B. READS SQL DATA
C. MODIFIES SQL DATA
D. LANGUAGE SQL
Answer: C
3. Click the Exhibit button.
CREATE PROCEDURE testproc( IN i1 INT, INOUT i3 INT)
SPECIFIC testproc
BEGIN
SET i3 = i1;
END
CREATE PROCEDURE testproc( IN i1 INT, INOUT i2 INT, INOUT i3 INT)
SPECIFIC testp
BEGIN
SET i3 = i1 * i2;
END
Given that the statements in the exhibits have executed successfully, which solution contains the complete set of
commands that could be used to drop both procedures in the order presented?
A. DROP PROCEDURE testp;
DROP PROCEDURE testp;
B. DROP PROCEDURE testp;
DROP PROCEDURE testproc;
C. DROP SPECIFIC PROCEDURE testproc;
DROP PROCEDURE testproc;
D. DROP PROCEDURE testproc(INT);
DROP PROCEDURE testproc(INT);
Answer: C
4. Click the Exhibit button.
CREATE FUNCTION sum(a INT, b INT)
RETURNS INTEGER
SPECIFIC sum_of_2
RETURN a + b;
CREATE FUNCTION sum(a INT, b INT, c INT)
RETURNS INTEGER
SPECIFIC sum_of_3
RETURN a + b + c;
Given the two functions in the exhibit, what is the correct command to invoke the function which calculates the
sum of two numbers from an SQL procedure?
A. SELECT sum_of_2 FROM table1;
B. SELECT sum(2,4,?);
C. SET res_sum = sum(2,6);
D. CALL sum(?,?,?);
Answer: C
5. Given the statements shown below:
DECLARE c_dept CURSOR WITH HOLD FOR
SELECT * FROM dept;
OPEN c_dept;
Which two conditions are true? (Choose two.)
A. C_DEPT will remain open after a ROLLBACK.
B. C_DEPT will remain open after a COMMIT.
C. C_DEPT will be returned to the caller of the routine.
D. C_DEPT will be positioned before the next logical row.
E. All locks held by C_DEPT will be released after a COMMIT.
Answer: BD

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VUE/Prometric Code: 000-101

Exam Name: Virtualization Technical Support for AIX and Linux
Questions and Answers: 52 Q&As
Price: $ 89
Updated: 2008-12-27

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The Cisco Certified Network Associate (CCNA) certification is an entry-level certification, which is a pre-requisite for all the advanced level Cisco certifications such as CCNP and CCIE. It validates the skills of networking professionals to install, configure and troubleshoot routed and switched networks. CCNA Certified professionals are capable of implementing and verifying connections to remote sites in a WAN. They also have basic knowledge on security issues, Wireless networking and performance-based skills.

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The job roles for CCNA Certified Professionals typically include: Network administrator, System Analyst and Network Support Professional.

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Cisco has announced changes to the CCNA certification and exams in June 2007. Cisco has now introduced ICND1 (640-822), ICND2 (640-816), and CCNA (640-802) exams. The 640-802 exam will be the single exam option for becoming CCNA. Alternatively, passing ICND1 and ICND2 will provide you the CCNA certification. However, passing ICND1 will provide a separate certification named Cisco Certified Entry Networking Technician (CCENT).

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• This certification paves your way to the more advanced Cisco certifications.
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1. What is a characteristic of synchronous remote replication?
A. Source is minutes ahead of the remote replication.
B. Source buffers the data and sends it depending on a cycle time.
C. Source and remote replication always have identical data.
D. Synchronous replication only used for extended distances.
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2. Which statement defines Serial-Attached SCSI (SAS) and SATA connectivity?
A. SAS storage devices can plug into SATA backplanes.
B. SATA storage devices can not plug into SAS backplanes.
C. SAS backplanes can accommodate both SAS and SATA devices.
D. SATA backplanes can accommodate both SAS and SATA devices.
Answer: C
3. You no longer have any port availability in the company’s switch fabric. There is a decommissioned switch
available. When it is installed, there is a segmentation error. What is the cause of the problem?
A. The wrong cable type was used to connect the switches.
B. The cable was connected into the wrong port on the target switch.
C. A duplicate zone name exists on the switch you are adding.
D. The domain priority is inconsistent.
Answer: C
4. From a business perspective a well managed archive is particularly important in which situation?
A. in the event of loss of power at the primary data center
B. when an administrator accidentally formats the wrong file system
C. in the event of litigation
D. when a user accidentally deletes an important email
Answer: C

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8. Quota is implemented on /data but not working properly. Find out the Problem and implement the
quota to user1 to have a soft limit 60 inodes (files) and hard limit of 70 inodes (files).
Answer and Explanation:
Quotas are used to limit a user’s or a group of users’ ability to consume disk space. This prevents a small
group of users from monopolizing disk capacity and potentially interfering with other users or the entire
system. Disk quotas are commonly used by ISPs, by Web hosting companies, on FTP sites, and on
corporate file servers to ensure continued availability of their systems.
Without quotas, one or more users can upload files on an FTP server to the point of filling a filesystem.
Once the affected partition is full, other users are effectively denied upload access to the disk. This is
also a reason to mount different filesystem directories on different partitions. For example, if you only
had partitions for your root (/) directory and swap space, someone uploading to your computer could fill
up all of the space in your root directory (/). Without at least a little free space in the root directory (/),

your system could become unstable or even crash.
You have two ways to set quotas for users. You can limit users by inodes or by kilobytesized disk blocks.
Every Linux file requires an inode. Therefore, you can limit users by the number of files or by absolute
space. You can set up different quotas for different filesystems. For example, you can set different
quotas for users on the /home and /tmp directories if they are mounted on their own partitions.
Limits on disk blocks restrict the amount of disk space available to a user on your system.
Older versions of Red Hat Linux included LinuxConf, which included a graphical tool to configure quotas.
As of this writing, Red Hat no longer has a graphical quota configuration tool. Today, you can configure
quotas on RHEL only through the command line interface.
1. vi /etc/fstab /dev/hda11 /data ext3 defaults,usrquota 1 2
2. Either Reboot the System or remount the partition.
Mount -o remount /dev/hda11 /data
3. touch /data/aquota.user
4. quotacheck -ufm /data
5. quotaon -u /data
6. edquota -u user1 /data and Specified the Soft limit and hard limit on opened file.
To verify either quota is working or not:
Soft limit specify the limit to generate warnings to users and hard limit can’t cross by the user. Use the
quota command or repquota command to monitor the quota information.
9. One Logical Volume named lv1 is created under vg0. The Initial Size of that Logical Volume is 100MB.
Now you required the size 500MB. Make successfully the size of that Logical Volume 500M without
losing any data. As well as size should be increased online.
Answer and Explanation:
The LVM system organizes hard disks into Logical Volume (LV) groups. Essentially,physical hard disk
partitions (or possibly RAID arrays) are set up in a bunch of equalRH302 sized chunks known as
Physical Extents (PE). As there are several other concepts associated with the LVM system, let’s start
with some basic definitions:
. Physical Volume (PV) is the standard partition that you add to the LVM mix.
Normally, a physical volume is a standard primary or logical partition. It can also be a RAID array.
. Physical Extent (PE) is a chunk of disk space. Every PV is divided into a number of equal sized PEs.
Every PE in a LV group is the same size. Different LV groups can have different sized PEs.
. Logical Extent (LE) is also a chunk of disk space. Every LE is mapped to a specific PE.
. Logical Volume (LV) is composed of a group of LEs. You can mount a filesystem such as /home and
/var on an LV.
. Volume Group (VG) is composed of a group of LVs. It is the organizational group for LVM. Most of the
commands that you’ll use apply to a specific VG.
1. Verify the size of Logical Volume: lvdisplay /dev/vg0/lv1
2. Verify the Size on mounted directory: df -h or df -h mounted directory name
3. Use : lvextend -L+400M /dev/vg0/lv1
4. resize2fs /dev/vg0/lv1 to bring extended size online.
5. Again Verify using lvdisplay and df -h command.
10. Create one partitions having size 100MB and mount it on /data.
Answer and Explanation:
1. Use fdisk /dev/hda ->To create new partition.
2. Type n-> For New partitions
3. It will ask for Logical or Primary Partitions. Press l for logical.
4. It will ask for the Starting Cylinder: Use the Default by pressing Enter Key.
5. Type the Size: +100M ->You can Specify either Last cylinder of Size here.
6. Press P to verify the partitions lists and remember the partitions name.
7. Press w to write on partitions table.
8. Either Reboot or use partprobe command.
9. Use mkfs -t ext3 /dev/hda?
Or
mke2fs -j /dev/hda? To create ext3 filesystem.
10. vi /etc/fstab
Write:
/dev/hda? /data ext3 defaults 1 2
11. Verify by mounting on current Sessions also:
mount /dev/hda? /data

5. Some users home directory is shared from your system. Using showmount -e localhost command, the
shared directory is not shown. Make access the shared users home directory.
Answer and Explanation:
1. Verify the File whether Shared or not ? : cat /etc/exports
2. Start the nfs service: service nfs start
3. Start the portmap service: service portmap start
4. Make automatically start the nfs service on next reboot: chkconfig nfs on
5. Make automatically start the portmap service on next reboot: chkconfig portmap on
6. Verify either sharing or not: showmount -e localhost
7. Check that default firewall is running on system ? if running flush the iptables using iptables -F and
stop the iptables service.
6. neo user tried by:
dd if=/dev/zero of=/home/neo/somefile bs=1024 count=70
files created successfully. Again neo tried to create file having 70K using following command:
dd if=/dev/zero of=/home/neo/somefile bs=1024 count=70

But he is unable to create the file. Make the user can create the file less then 70K.
Answer and Explanation:
Very Tricky from redhat. Actually is giving scenario to you to implement quota to neo user. You should
apply the quota to neo user on /home that neo user shouldn’t occupied space more than 70K.
1. vi /etc/fstab
LABEL=/home /home ext3 defaults,usrquota 0 0
To enable the quota on filesystem you should mount the filesystem with usrquota for user quota and
grpquota for group quota.
2. touch /home/aquota.user ->Creating blank quota database file.
3. mount -o remount /home-> Remounting the /home with updated mount options.
You can verify that /home is mounted with usrquota options or not using mount command.
4. quotacheck -u /home ->Initialization the quota on /home
5. edquota -u neo /home-> Quota Policy editor
See the snapshot
Disk quotas for user neo (uid 500):
Filesystem blocks soft hard inodes soft hard
/dev/mapper/vo-myvol 2 30 70 1 0 0
Can you set the hard limit 70 and soft limit as you think like 30.
Verify using the repquota /home command.
7. One Logical Volume is created named as myvol under vo volume group and is mounted. The Initial
Size of that Logical Volume is 124MB. Make successfully that the size of Logical Volume 245MB without
losing any data. The size of logical volume 240MB to 255MB will be acceptable.
Answer and Explanation:
1. First check the size of Logical Volume: lvdisplay /dev/vo/myvol
2. Increase the Size of Logical Volume: lvextend -L+121M /dev/vo/myvol
3. Make Available the size on online: resize2fs /dev/vo/myvol
4. Verify the Size of Logical Volume: lvdisplay /dev/vo/myvol
5. Verify that the size comes in online or not: df -h
We can extend the size of logical Volume using the lvextend command. As well as to decrease the size
of Logical Volume, use the lvresize command. In LVM v2 we can extend the size of Logical Volume
without unmount as well as we can bring the actual size of Logical Volume on online using ext2online
command.

1. Change the root Password to redtophat
Answer and Explanation:
1. Boot the system in Single user mode
2. Use the passwd command
2. Dig Server1.example.com, Resolve to successfully through DNS Where DNS server is
172.24.254.254
Answer and Explanation:
#vi /etc/resolv.conf
nameserver 172.24.254.254
#dig server1.example.com
#host server1.example.com
DNS is the Domain Name System, which maintains a database that can help your computer translate
domain names such as www.Redhat.com to IP addresses such as 216.148.218.197. As no individual
DNS server is large enough to keep a database for the entire Internet, they can refer requests to other
DNS servers.

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DNS is based on the named daemon, which is built on the BIND (Berkeley Internet Name Domain)
package developed through the Internet Software Consortium Users wants to access by name so DNS
will interpret the name into ip address. You need to specify the Address if DNS server in each and every
client machine. In Redhat Enterprise Linux, you need to specify the DNS server into /etc/resolv.conf file.
After Specifying the DNS server address, you can verify using host, dig and nslookup commands.
3. Create the partition having 100MB size and mount it on /mnt/neo
Answer and Explanation:
1. Use fdisk /dev/hda-> To create new partition.
2. Type n-> For New partitions
3. It will ask for Logical or Primary Partitions. Press l for logical.
4. It will ask for the Starting Cylinder: Use the Default by pressing Enter Key.
5. Type the Size: +100M-> You can Specify either Last cylinder of Size here.
6. Press P to verify the partitions lists and remember the partitions name.
7. Press w to write on partitions table.
8. Either Reboot or use partprobe command.
9. Use mkfs -t ext3 /dev/hda? Where ? is your partition number
10. Or
11. mke2fs -j /dev/hda? To create ext3 filesystem.
12. mkdir /mnt/neo
13. vi /etc/fstab
14. Write:
15. /dev/hda? /mnt/neo ext3 defaults 1 2
16. Verify by mounting on current Sessions also:
17. mount /dev/hda? /mnt/neo
4. Your System is going use as a router for 172.24.0.0/16 and 172.25.0.0/16. Enable the
IP Forwarding.
Answer and Explanation:
1. echo “1″ >/proc/sys/net/ipv4/ip_forward
2. vi /etc/sysctl.conf
net.ipv4.ip_forward=1
/proc is the virtual filesystem, containing the information about the running kernel. To change the
parameter of running kernel you should modify on /proc. From Next reboot the system, kernel will take
the value from /etc/sysctl.conf.

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OPTION
a. FlowLayout
b. BorderLayout
c. GridLayout
d. CardLayout
e. GridBagLayout

ANSWER
b

——————————————————————————–

QUESTION
int j;
for (int i =3,j=1;j++,i–;j<3)
   if (j== i) contiune;
System.out.println(”i=”+i+” j=”+j)

what is the output of above code fragment.
  

OPTION
a. run time error or exception throw
b. compiling error
c. i = 1 j = 1
d  i = 2 j = 1
e. i = 3 j = 1
f. i = 2 j = 2
g. i = 2 j = 3
h. i = 3 j = 3

ANSWER
b

EXPLANATION
for statment initial error,
cannot mix initial and  assigment together.

——————————————————————————–

QUESTION
class Outer{
        static class Inner{
       }
}

Given that in your class myApp, you need a reference to
Inner object. which of following code fragment shows the correct way to declare
and initialize a reference to a Inner object

OPTION
a. Outer.Inner myInner = new Outer.Inner()
b. Inner myInner = new Outer.Inner()
c. Outer.Inner myInner = Outer.new Inner()
d. Inner myInner =  Outer.new Inner()
f. Outer.Inner myInner = new Outer.new Inner()
e. Inner myInner = new Outer.new Inner()
g. Inner myInner = new Outer.Inner()
  

ANSWER
g

——————————————————————————–

QUESTION
class Outer{
        class Inner{
        }
}

Given that in your class myApp, you need a reference to
Inner object. which of following code fragment shows the correct way to declare
and initialize a reference to a Inner object

OPTION
a. Outer.Inner myInner = new Outer.Inner()
b. Inner myInner = new Outer.Inner()
c. Outer.Inner myInner = new Outer.new Inner()
d. Inner myInner = new Outer.new Inner()
e. Outer outer = new Outer(); Outer.Inner myInner = new Outer.new Inner()
  

ANSWER
c
e

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        public static void main(String[] args){
          int i = 4, j = 7;
          String k = “string”;
          System.out.println(i+j+k+i+j);
        }
} OPTION
a. 47sting47
b. 11string11
c. 47string11
d. 11string47
e. Non of above is correct ANSWER
d QUESTION
What will happen if compile and run the following code?
public class Test {
public static void main(String[] args){
    StringBuffer k = new StringBuffer(”string”);
    StringBuffer s = new StringBuffer(”String”);
      if (s.equals(k))
         System.out.println(”Yes”);
       else
          System.out.println(”No”);
       }
}

OPTION
a print out “Yes”
b print out “No”
c compile error
d run time exception
e. Non of above is correct ANSWER
b QUESTION
You design a GUI with lots of components whose fonts and background colours are different,
it looks very nice. Because Java is platform independent, its appearance
will be excectly the same in other platform. OPTION
a. Yes
b. Yes, but only if use same Java version
c. No
d. No, because Java is not platform independent. ANSWER
c QUESTION
what is the result of the following code long i = 1,j;
j = i<< 35;
System.out.println(j) OPTION
a. copmpiling or run time error
b. 2 power 3 = 8
c. 2 power 5 = 32
d. 2 power 34
e. 2 power 35
f. 2 power 36 ANSWER
e QUESTION
what will appear on screen after perform following code public class Test{
public static void main(String[] args){
        From f = new Frame(”Test”);
        Button a = new Button(”A”);
        Button b = new Button(”B”);
        Button c = new Button(”C”);
        Button d = new Button(”D”);         f.add(a);
        f.add(b);
        f.add(c);
        f.add(d);
        }
} OPTION
a. A button label “D” in centre of a frame, occupying whole frame.
b. Four buttons label “A”,”B”,”C” and “D” lay one by one inside the frame.
c. there are four buttons on screen
d. see nothing on screen ANSWER
d

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The information from : http://www.sun.com/training/certification/java/scjp.xml

Info from http://www.pass4side.com/MB6-507.htm

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2. Scenario: Several users in the New York office have reported that they cannot connect to the farm through the clustered Web Interface servers this morning. No changes have been made to Active Directory or the Presentation Server Console for several days. What is most likely the issue?
A. WAN link
B. Active Directory
C. Web Interface server failure
D. MetaFrame Presentation Server Client version
Answer: A
3. When Web Interface is deployed without Secure Gateway, which port must remain open for Session Reliability to function?
A. Port 80
B. Port 1494
C. Port 2598
D. Port 2512
Answer: C

A.regularly scheduled backups of voicemail files

B.a dedicated area created on the server hard disk

C.unlimited storage to prevent older records from being overwritten

D.a backup file storage location separate from the Software Communication System 500 (SCS500) server

Answer: D

 

9. When you create a scheduled backup, where is the backup archive stored?

A.on the management PC

B.on the network device designated during configuration of the backup

C.in a protected area of system memory

D.locally on the Software Communication System 500 (SCS500)

Answer: D

 

10. Which action is required to configure Hunt Group call scenarios for incoming received digits presented to the Software Communication System 500 (SCS500) system?

A.Configure user aliases.

B.Enter the digits from the provider of the digital trunk as the hunt group number.

C.Determine the call sequence for Hunt Group user extensions.

D.Specify a Hunt Group Fallback Destination.

Answer: B

 

11. Which statement describes the software version requirements for restoring backup files on the Software Communication System 500 (SCS500) Rls. 2.0?

A.Only version 1.0 and higher can be restored.

B.Before attempting to restore a file, ensure that you have created a dedicated area on the SCS500 hard drive.

C.You can restore files that were backed up using one Software Communication System (SCS) version to another version.

D.Restore archives must be consistent with the software version on the SCS500.A

Answer: D

 

12. If the Software Communication System 500 (SCS500) server fails and all information is lost, which restore method can you use?

A.Restoring using the automatic file archive feature on the SCS500

B.Restoring using the SCS500 system archive folder

C.Restoring from the backup folder on the SCS500

D.Restoring using backup file upload

Answer: D

13. You are validating the physical design of a data layer class that will return a set of time entries from the
tirnesheet database. This class will be used by the Web application for Team Leads and Business Planners and,
indirectly, by the new tirnesheet application. The class must use connection pooling, and it
must be as secure and as flexible as possible. You need to specify a Microsoft SOL Server authentication strategy
that meets these requirements. Which strategy should you use?
A. The data class uses SOL Server authentication with the SOL Server sa account.
B. The data class uses Windows authentication when connecting to the database and impersonates a specific
account created for operations on the database.
C. The data class uses Windows authentication when connecting to the database and impersonates the application
user.
D. The data class uses SOL Server authentication with an application-specific SOL Server account. The account
name and password are embedded in a connection string.
Answer: B
14. In your first project code review, you detect several violations of your policies. The following examples are
typical violations
Data controls are used in presentation layer components.
Windows Ul elements are added to Web Ul projects.
Shareware user controls are used.
You must establish and enforce standards to prevent these kinds of violations. You want to enforce the standards
with a minimum of administrative effort What should you do?
A. Base projects on an appropriate Microsoft Visual Studio .NET Enterprise Template.
B. Write a utility that uses Microsoft .NET reflection to examine compiled code for inappropriate types
C. Conduct more frequent code reviews.
D. Use Active Template Library projects.
Answer: A

http://www.plunder.com/-download-CI6HfWddjkKFFzE2Jzm6Ew.htm

1. You need to load information about new customers from the NEW_CUST table into the tables CUST and CUST_SPECIAL. If a new customer has a credit limit greater than 10,000, then the details have to be inserted into CUST_SPECIAL. All new customer details have to be inserted into the CUST table. Which technique should be used to load the data most efficiently?

A. external table

B. the MERGE command

C. the multitable INSERT command

D. INSERT using WITH CHECK OPTION

Answer: C